Question

Differentiation of cot inverse of root

Answer 1

Dear student
$$\begin{gathered} \frac{\mathrm{d}}{\mathrm{dx}}\left[{\cot }^{-1}\left(\sqrt{\mathrm{x}}\right)\right] \\ =\left(\frac{-1}{{\left(\sqrt{\mathrm{x}}\right)}^2+1}\right)\frac{\mathrm{d}}{\mathrm{dx}}\left[\sqrt{\mathrm{x}}\right] \\ =\frac{-1}{2\sqrt{\mathrm{x}}\left(\mathrm{x}+1\right)} \end{gathered}$$
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