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Question

Differentitate with respect to x exsinx(x2+2)3.

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Solution

We have,

Let y=exsinx(x2+2)3

y=exsinx(x2+2)3

Applying formula

ddx(I.II.III)=I.IIddxIII+I.IIIddxII+II.IIIddxI

Now,

dydx=exsinxddx(x2+2)3+ex(x2+2)ddxsinx3+sinx(x2+2)ddxex

=exsinx(3)(x2+2)4(2x)+ex(x2+2)cosx+sinx(x2+2)ex

=6xexsinx(x2+2)4+ex(x2+2)cosx+sinx(x2+2)ex

Hence, this is the answer.

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