Digit sum of a number is defined as the sum of the digit till a single digit number is obtained.N = 2! +3! +4! + 5! +……………….10 !. Find the digit sum of N ?

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Solution

The correct option is A 8
Option (a)

Digit sum is nothing but the remainder obtained when the number is divided by 9. Thus from 6! To 10! the number is completely divisible by 9. Hence, digit sum is 0 1!+2!+3!+4!+5! = 1+2+6+24+120 = 153, which is completely divisible by 9.
Hence, digit sum is 0

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Digit sum of a number is defined as the sum of the digit till a single digit number is obtained.N = 2! +3! +4! + 5! +……………….10 !. Find the digit sum of N ?

The correct option is A 8Option (a) Digit sum is nothing but the remainder obtained when the number is divided by 9. Thus from 6! To 10! the number is completely divisible by 9. Hence, digit sum is 0 1!+2!+3!+4!+5! = 1+2+6+24+120 = 153, which is completely divisible by 9. Hence, digit sum is 0

The correct option is A 8
Option (a)

Digit sum is nothing but the remainder obtained when the number is divided by 9. Thus from 6! To 10! the number is completely divisible by 9. Hence, digit sum is 0 1!+2!+3!+4!+5! = 1+2+6+24+120 = 153, which is completely divisible by 9.
Hence, digit sum is 0