Digit sum of a number is defined as the sum of the digit till a single digit number is obtained. N = 2! +3! +4! + 5! +……………….10!. Find the digit sum of N?

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Solution

The correct option is A 8
From 6! To 10! the digit sum of each term=9, because each term is divisible by 9.
Digit sum of 2!+3!+4!+5! = 17
Digit sum = 62 = 8

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Digit sum of a number is defined as the sum of the digit till a single digit number is obtained. N = 2! +3! +4! + 5! +……………….10!. Find the digit sum of N?

The correct option is A 8From 6! To 10! the digit sum of each term=9, because each term is divisible by 9. Digit sum of 2!+3!+4!+5! = 17 Digit sum = 62 = 8

The correct option is A 8
From 6! To 10! the digit sum of each term=9, because each term is divisible by 9.
Digit sum of 2!+3!+4!+5! = 17
Digit sum = 62 = 8