Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction-i CH 4 g - H 2 O g - CO g -3 H 2 g Write as expression for K p for the above reactionii CH 4 g - H 2 O g - CO g -3 H 2 g How will the values of Kp and compositioon of equilibrium mixture be affected byi Increasing the pressureii Increasing the temperatureiii Using a catalyst-

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Byju's Answer

Standard XII

Chemistry

Vant Hoff's Equation and Effect of Temperature on Equilibrium Constant

Dihydrogen ga...

Question

Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:
(i) $C H_{4} (g) + H_{2} O (g) \leftrightarrow C O (g) + 3 H_{2} (g)$
Write as expression for $K_{p}$ for the above reaction

(ii) $C H_{4} (g) + H_{2} O (g) \leftrightarrow C O (g) + 3 H_{2} (g)$
How will the values of $K_{p}$ and compositioon of equilibrium mixture be affected by
(i) Increasing the pressure
(ii) Increasing the temperature
(iii) Using a catalyst?

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Solution

$K_{p} = \frac{P_{c o} \times P_{H_{2}}^{3}}{P_{C H_{4}} \times P_{H_{2} O}}$

(i) According to Le Chatelier's principle, the equilibrium will shift in the backward direction.
(ii) According to Le Chatelier's principle, as the reaction is endothermic, the equilibrium will shift in the forward direction.
(iii) The equilibrium of the reaction is not affected by the presence of a catalyst. A catalyst only increases the rate of a reaction. Thus, equilibrium will be attained quickly.

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Similar questions

Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:

(a) Write as expression for K_p for the above reaction.

(b) How will the values of K_p and composition of equilibrium mixture be affected by

(i) Increasing the pressure

(ii) Increasing the temperature

(iii) Using a catalyst?

Q. Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:

{C H}_{4} (g) + H_{2} O (g) ⇌ C O (g) + 3 H_{2} (g)

(a) Write as expression for

K_{p}

for the above reaction.

(b) How will the values of

K_{p}

and composition of equilibrium mixture be affected by
(i) increasing the pressure,
(ii) Increasing the temperature and
(iii) Using a catalyst?

Which of the following reactions will get affected by increasing the pressure?
Also, mention whether change will cause the reaction to go into forward or backward direction.
(i) $C O C l_{2} (g) \leftrightarrow C O (g) + C l_{2} (g)$
(ii) $C H_{4} (g) + 2 S_{2} (g) \leftrightarrow C S_{2} (g) + 2 H_{2} S (g)$
(iii) $C O_{2} (g) + C (s) \leftrightarrow 2 C O (g)$
(iv) $2 H_{2} (g) + C O (g) \leftrightarrow C H_{3} O H (g)$
(v) $C a C O_{3} (s) \leftrightarrow C a O (s) + C O_{2} (g)$
(vi) $4 N H_{3} (g) + 5 O_{2} (g) \leftrightarrow 4 N O (g) + 6 H_{2} O (g)$