Dilute aqueous $K M n O_{4}$ , at room temperature reacts with R -CH =CH -R to give

R – CHO

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R – COOH

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RCHOH – CHOHR

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C O_{2} + H_{2} O

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Solution

The correct option is C RCHOH – CHOHR

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Similar questions

K M n O_{4}

K M n O_{4}

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C H_{2} = C H - O C H_{3}

R - C - H = C H_{2}

B_{2} H_{6}

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