Dilute sulphuric acid on electrolysis liberates :

oxygen of anode

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oxygen at the cathode

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hydrogen at the anode

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{S O}_{2}

at the anode

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Solution

The correct option is C oxygen of anode
In electrolysis of dilute sulphuric acid Water oxidise at anode and liberates oxygen gas. The reaction is as follows:
At anode:
$H_{2} O \to O_{2} + 4 e^{-} + 2 H^{+}$ .

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Similar questions

Q. A dilute solution of sulphuric acid during electrolysis liberate O

_{2}

gas at the anode.

Q. During the electrolysis of dilute sulphuric acid, the following process is possible at anode.

Q. On electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be:

Q. In electrolysis of dilute

H_{2} S O_{4}

, what is liberated at anode?

Which of the following statements are correct?

a) The electrolysis of aqueous NaCl produces hydrogen gas at the cathode and chlorine gas at the anode .

b) The electrolysis of a $C u S O_{4}$ solution using Pt electrodes causes the liberation of $O_{2}$ at the anode and the deposition of copper at the cathode .

c) Oxygen and hydrogen are produced at the anode and cathode during the electrolysis of dilute aqueous solution of $H_{2} S O_{4}$ .

d) All electrolytic reactions are redox reactions .

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Dilute sulphuric acid on electrolysis liberates :

The correct option is C oxygen of anodeIn electrolysis of dilute sulphuric acid Water oxidise at anode and liberates oxygen gas. The reaction is as follows:At anode:H2O→O2+4e−+2H+.

The correct option is C oxygen of anode
In electrolysis of dilute sulphuric acid Water oxidise at anode and liberates oxygen gas. The reaction is as follows:
At anode:
$H_{2} O \to O_{2} + 4 e^{-} + 2 H^{+}$ .