Dimension of electrical resistance is :

[M L^{2} T^{- 3} A^{- 1}]

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[M L^{2} T^{- 3} A^{- 2}]

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[M L^{3} T^{- 3} A^{- 2}]

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[M L^{- 1} T^{3} A^{2}]

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Solution

The correct option is B $[M L^{2} T^{- 3} A^{- 2}]$
We know that Power, $P = I^{2} R$
Dimensions of Power are that of Force times velocity, i.e. $M L T^{- 2} \times L T^{- 1} = M L^{2} T^{- 3}$
Thus, $M L^{2} T^{- 3} = A^{2} | R |$ , or $| R | = M L^{2} T^{- 3} A^{- 2}$

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Similar questions

	Column I (Physical quantity)		Column II (Dimensional formula)
(A)	Premittivity of free space	(p)	$[M^{0} L^{0} T^{- 1}]$
(B)	Radiant flux	(q)	$[M L^{3} T^{- 3} A^{- 2}]$
(C)	Resistivity	(r)	$[M L^{2} T^{- 3}]$
(D)	Hubble constant	(s)	$[M^{- 1} L^{- 3} T^{4} A^{2}]$