Dimension of velocity gradient is

[M^{0} L^{0} T^{- 1}]

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[M L^{- 1} T^{- 1}]

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[M^{0} L T^{- 1}]

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[M L^{0} L^{- 1}]

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Solution

The correct option is A $[M^{0} L^{0} T^{- 1}]$
Velocity gradient = $\frac{V e l o c i t y}{D i s t a n c e}$
Thus $[V e l o c i t y G r a d i e n t] = \frac{L T^{- 1}}{L} = M^{0} L^{0} T^{- 1}$

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Dimension of velocity gradient is

The correct option is A [M0L0T−1]Velocity gradient = VelocityDistanceThus [Velocity Gradient]=LT−1L=M0L0T−1

The correct option is A $[M^{0} L^{0} T^{- 1}]$
Velocity gradient = $\frac{V e l o c i t y}{D i s t a n c e}$
Thus $[V e l o c i t y G r a d i e n t] = \frac{L T^{- 1}}{L} = M^{0} L^{0} T^{- 1}$