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Byju's Answer
Standard XII
Physics
Dimensional Analysis
Dimensional f...
Question
Dimensional formula for Angular momentum is:
A
M
L
2
T
−
1
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B
M
1
L
3
T
−
1
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C
M
1
L
1
T
−
1
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D
M
L
3
T
−
2
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Solution
The correct option is
A
M
L
2
T
−
1
Angular Momentum
=
m
v
r
=
M
×
L
T
−
1
×
L
=
M
L
2
T
−
1
Hence, option A is correct.
Suggest Corrections
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Similar questions
Q.
Match the following physical quantities with their respective dimensional formula:
(a) Angular Momentum
(e)
[
M
L
2
T
−
3
]
(b) Impulse
(f)
[
M
L
2
T
−
1
]
(c) Pressure
(g)
[
M
L
T
−
1
]
(d) Power
(h)
[
M
L
−
1
T
−
2
]
Q.
The dimensional formula of a physical quantity is
[
M
1
L
1
T
−
2
]
. What is its SI unit?
Q.
Some physical constants are given in List - I and their dimensional formulae are given in List
- II. Match the following :
List - I
List - II
A) Planck's constant
e)
[
M
L
−
1
T
−
2
]
B) Gravitational constant
f)
[
M
L
1
T
−
1
]
C) Bulk modulus
g)
[
M
L
2
T
−
1
]
D) Linear momentum
h)
[
M
−
1
L
3
T
−
2
]
Q.
The dimensional formula
M
−
1
L
3
T
−
2
refers to :
Q.
Match the physical quantities given in Column I with suitable dimensions expressed in Column
II.
Column I
Column II
a) Angular momentum
g)
M
L
2
T
−
2
b) Latent heat
h)
M
L
2
Q
−
2
c) Torque
i)
M
L
2
T
−
1
d) Capacitane
j)
M
L
3
T
−
1
Q
−
2
e) Inductance
k)
M
−
1
L
−
2
T
2
Q
2
f) Resistivity
l)
L
2
T
−
2
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