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Question

Dimensional formula of self inductance is:

A
MLT2A2
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B
ML2T1A2
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C
ML2T2A2
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D
ML2T2A1
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Solution

The correct option is C ML2T2A2
The magnetic flux is given by
ϕ=LI
The dimensional formula of self inductance, [L]=[BA][I]. . . . . .(1)
Force, f=qvB
[M1L1T2]=[TA].[L1T1].[B]
[B]=[M1T2A1]
[BA]=[M1L2T2A1]
From equation (1), we get
[ϕ]=[M1L2T2A2]
The correct option is C.


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