Dimensional formula of self inductance is:

M L T^{- 2} A^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M L^{2} T^{- 1} A^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M L^{2} T^{- 2} A^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M L^{2} T^{- 2} A^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $M L^{2} T^{- 2} A^{- 2}$
The magnetic flux is given by
$ϕ = L I$
The dimensional formula of self inductance, $[L] = \frac{[B A]}{[I]}$ . . . . . .(1)
Force, $f = q v B$
$[M^{1} L^{1} T^{- 2}] = [T A] . [L^{1} T^{- 1}] . [B]$
$[B] = [M^{1} T^{- 2} A^{- 1}]$
$[B A] = [M^{1} L^{2} T^{- 2} A^{- 1}]$
From equation (1), we get
$[ϕ] = [M^{1} L^{2} T^{- 2} A^{- 2}]$
The correct option is C.

Suggest Corrections

Similar questions

L

L = r p sin θ

r

P

M L^{2} T^{- 2}

M L^{2} T^{- 3}

Join BYJU'S Learning Program