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Units and Dimensions

Dimensional f...

Question

Dimensional formula of Torque is:

A

{M L T}^{- 2}

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B

{M L}^{2} T^{- 2}

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C

{M L}^{2} T^{- 3}

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D

{M L T}^{- 3}

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Solution

The correct option is B ${M L}^{2} T^{- 2}$
The correct option is B.

Torque is a physical computation with the dimension of force times distance. Its SI unit is newton meter (N m). It also has unit as joule per radian.

$T o q u e = F o r c e \times D i s t a n c e$

$= N \times m$

In $M K S$ unit it is Kg m per $s^{2} \times m .$

Thus its dimensional formula is $M L^{2} T^{- 2} .$

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(a) Angular Momentum	(e) $[{M L}^{2} T^{- 3}]$
(b) Impulse	(f) $[{M L}^{2} T^{- 1}]$
(c) Pressure	(g) $[M L T^{- 1}]$
(d) Power	(h) $[{M L}^{- 1} T^{- 2}]$

Q. Match the physical quantities given in Column I with suitable dimensions expressed in Column II.

Column I	Column II
a) Angular momentum	1) $M^{- 1} L^{3} T^{- 2}$
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c) Gravitational constant	3) ${M L}^{2} T^{- 2}$
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a) Pa-s	e) $[L^{2} T^{- 2} K^{- 1}]$
b) ${N m K}^{- 1}$	f) ${M L T}^{- 3} K^{- 1}$
c) ${J k g}^{- 1} k^{- 1}$	g) ${M L}^{- 1} T^{- 1}$
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{M L}^{2} T^{- 2}

The dimensional formula of

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