Dimensional formula of universal gravitational constant $G$ is-

M^{- 1} L^{3} T^{- 2}

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M^{- 1} L^{2} T^{- 2}

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M^{- 2} L^{3} T^{- 2}

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M^{- 2} L^{2} T^{- 2}

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Solution

The correct option is A $M^{- 1} L^{3} T^{- 2}$
Gravitational force acting between two objects of masses $m_{1}$ and $m_{2}$ separated by distance $r$ , $F = \frac{G m_{1} m_{2}}{r^{2}}$
$⟹$ $G = \frac{F r^{2}}{m_{1} m_{2}}$
Thus dimensional formula of $G$ is $\frac{[M L T^{- 2}] [L]^{2}}{[M]^{2}}$
$⟹$ $G = M^{- 1} L^{3} T^{- 2}$

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