Dimensions $[M L^{- 1} T^{- 1}]$ are related to

Torque

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Coefficient of viscosity

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Solution

The correct option is B Coefficient of viscosity
We know that
Coefficient of viscosity= $\frac{f o r c e / a r e a}{v e l o c i t y g r a d i e n t}$
$[η] = \frac{[M L T^{- 2}] / [L^{2}]}{[L T^{- 1}] / [L]}$
$= [M L^{- 1} T^{- 1}]$

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