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Standard XII

Chemistry

Relative Lowering of Vapour Pressure

Dimer of acet...

Question

Dimer of acetic acid in liquid benzene is in equilibrium with acetic acid monomer at certain temperature and pressure. If 25% of the dimer molecules are separated out then

Freezing point of the solution reduces

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Average molar mass of solute increases

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Boiling point of solution increases

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Molar mass of solute decreases

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Solution

The correct option is D Freezing point of the solution reduces
$n_{C_{4} H_{10}} = \frac{10.44}{58} \Rightarrow 0.18$

$m = \frac{0.18}{200} \times 1000 \Rightarrow 0.9$
$Δ T_{f} = 5.12 \times 0.9 \Rightarrow 4.608$
$T_{f} = 5.5 - 4.608 \Rightarrow {0.892}^{\circ} C$

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Dimer of acetic acid in liquid benzene is in equilibrium with acetic acid monomer at certain temperature and pressure. If 25% of the dimer molecules are separated out then

The correct option is D Freezing point of the solution reducesnC4H10=10.4458⇒0.18m=0.18200×1000⇒0.9ΔTf=5.12×0.9⇒4.608Tf=5.5−4.608⇒0.892∘C

The correct option is D Freezing point of the solution reduces
$n_{C_{4} H_{10}} = \frac{10.44}{58} \Rightarrow 0.18$

$m = \frac{0.18}{200} \times 1000 \Rightarrow 0.9$
$Δ T_{f} = 5.12 \times 0.9 \Rightarrow 4.608$
$T_{f} = 5.5 - 4.608 \Rightarrow {0.892}^{\circ} C$