Question

Dinesh sold his motorcycle to Naveen at a loss of $28\%$Naveen spent $Rs.1680$ on its repair and sold the motorcycle to Saran for $Rs.35,910$ making a profit of $12.5\%$ Find cost of the motorcycle for Dinesh.

Answer 1

Let $C.P$ of motorcycle for Dinesh be $=Rs.x$
Loss percentage $=28\%$

So, $S.P$ of motorcycle $=\frac{72}{100}x=0.72x$

$C.P$ for Naveen including the cost of repair $=(0.72x+1680)$ ........(i)

$S.P$ of motor for Naveen $=Rs.35910$
Profit amount $=35910-(0.72x+1680)$ .......(ii)

Profit percentage $=\frac{\text{profit}}{\text{C.P}}\times 100=12.50\%$
Substitute values of equations (i) and (ii), we get
$\Rightarrow (35910-(0.72x+1680\left)\right)\times \frac{100}{(0.72x+1680)}=12.5$

$\Rightarrow \frac{(3423-0.72x)}{(0.72x+1680)}=\frac{125}{100}$
$\Rightarrow (3423-0.72x)\times 100=125\times (0.72x+1680)$

$\Rightarrow 3423000-72x=9x+21000$

$\Rightarrow 3423000-21000=9x+72x$

$\Rightarrow 3402000=81x$

$\Rightarrow x=42000$