Question

Ding's diner advertised this daily lunch special : "Choose 1 item from each column-only 4.95$!" Thus, each daily lunch special consists of a salad, a soup, a sandwich, and a drink.

Salads	Soups	Sandwiches	Drinks
cole slaw	onion	meat load	milk
lettuce	tomato	chicken	cola
potato		hamburger	coffee
		ham tenderloin	tea

How many different daily lunch specials are possible?

• A. $4$
• B. $14$
• C. $30$
• D. $120$
• E. $190$

Answer 1

Answer: (D)

$120$

Number of possible salads $=3$
Number of possible Soups $=2$
Number of possible Sandwiches $=5$
Number of possible Drinks $=4$
Hence, a meal the total number of permutations will be
3 2 5 4
------- --------- ---------- ---------
Salads Soups Sandwiches Drinks.
Number of ways to fill the place of salads is $3$, similarly number of ways to fill the place of soups is $2$, sandwiches $5$ and drinks $4$.

Hence, the required permutation is $3\times 2\times 5\times 4=120$.