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Reverse Bias

Diodes D-1 ...

Question

Diodes $D - 1$ and $D_{2}$ shown in circuit are silicon diodes.The voltage drop (V) across the diode $D_{2}$ and the power dissipated (P) by this diode $(D_{2})$ are

V_{D_{2}} = 0.7 V

and

P_{D_{2}} = 0 W

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V_{D_{2}} = 5 V

and

P_{D_{2}} = 0 W

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V_{D_{2}} = 0.7 V

and

P_{D_{2}} = 0.7 W

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V_{D_{2}} = 5.0 V

and

P_{D_{2}} = 5 W

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Solution

The correct option is D $V_{D_{2}} = 0.7 V$ and $P_{D_{2}} = 0 W$
Since diode $D_{1}$ is forward biased, so voltage drop across it is $0.7 V$
As the diodes $D_{1}$ and $D_{2}$ are connected in parallel, so voltage drop across is equal to that across $D_{1}$ i.e. $0.7 V$
Since, $D_{2}$ is reversed biased, so no current flows through it and so power dissipated by $D_{2}$ is zero.

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