Dipole moment of a certain diatomic molecule X-Y is 0.38 D. If X-Y bond length is 158 pm, the percentage of electronic charge developed on ‘X’ atom is: ___

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Solution

$δ^{+} = \frac{μ_{x y}}{d_{x - y}} = \frac{0.38 \times 10^{- 18}}{158 \times 10^{- 10}} = 2.4 \times 10^{- 11}$
$% e l e c t r o n c h a r g e = \frac{2.4 \times 10^{- 11}}{4.8 \times 10^{- 10}} \times 100 = 5 %$

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Dipole moment of a certain diatomic molecule X-Y is 0.38 D. If X-Y bond length is 158 pm, the percentage of electronic charge developed on ‘X’ atom is: ___

δ+=μxydx−y=0.38×10−18158×10−10=2.4×10−11 % electron charge=2.4×10−114.8×10−10×100=5%

$δ^{+} = \frac{μ_{x y}}{d_{x - y}} = \frac{0.38 \times 10^{- 18}}{158 \times 10^{- 10}} = 2.4 \times 10^{- 11}$
$% e l e c t r o n c h a r g e = \frac{2.4 \times 10^{- 11}}{4.8 \times 10^{- 10}} \times 100 = 5 %$