Question

Dipole moment of $H_{2}S$ is $0.95$D. Calculate the bond moment if the bond angle is ${97}^0$.

$(cos{48.5}^0=0.662)$

Answer 1

$\mu =2$ ( S-H bond moment ) $\times \cos \left(\frac{\theta }{2}\right)$

$\Rightarrow 0.95=2$ ( S-H bond moment ) $\times \cos$

$\Rightarrow 0.95=2$ ( S-H bond moment ) $\times 0.663$

$\Rightarrow S-H$ bond moment $=\frac{0.95}{1.326}=0.716\simeq \mathrm{0.72.}$

Hence, the answer is $\mathrm{0.72.}$