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Directions for the next TWO questions:
A chemistry lab has 5 beakers, each having a different capacity.

I. Beaker A can hold twice as much liquid as beaker B
II. Beaker B can hold four and one-half times as much liquid as beaker C
III. Beaker C can hold half as much liquid as beaker D
IV. Beaker D can hold half as much liquid as beaker E
V. Beaker E can hold more liquid than beaker C, but less than beaker A

1. Which of the following represents the descending order of capacities of the beakers?

A
E, C, D, A, and B
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B
A, B, E, D, and C
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C
A, B, D, E, and C
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D
B, D, H, A, and C
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Solution

The correct option is B A, B, E, D, and C
It is very clear from the statements that C has the least capacity. Let us take the capacity of C as X
From III → Capacity of D = 2X
From IV → Capacity of E = 4X
From II → Capacity of B = 4.5X
From I → Capacity of A = 9X

The correct order of capacity in decreasing order is → A > B > E > D > C

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