CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Discuss continuity of cosine, cosecant, secant and cotangent function.

Open in App
Solution

a)


f(x)=cosx

utCIR

LhLlimxcRhLlimxc+f(x)

limf(ch)=lim410cos(c+h)

limcos(ch)=lim410cosccoshsincsinh

lim410cosccosh+sincsinhcosc

=cosc

lLh=Rhc=f(x)

cosine is continuous


b)


f(x)=cosecx

=1sinx

this is continuous xstsinx0

xnπ1nz/

so, cosecx is cont all all nR

stxnπ1nz/


c)


secx=1cosx

f is cont. xIRstcosx0

x(2n+1)π/2,nz/


d)


f(x)=cotx=cosxsinx

f is cont. for auxIRst

sinx0

xnπ1nz/

So,cotx is continuous at au not numbers except x=nπ1nz/


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Differentiation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon