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Question

Discuss the continuity and differentiability of the function,
f(x)=⎢ ⎢ ⎢x1+|x||x|>1x1|x||x|1⎥ ⎥ ⎥

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Solution

limx1f(x)=11+1=12
limx1+f(x)=111 = Doeiut exit
Not continues 1 Not differeatiable


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