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Question

Discuss the continuity of fx=2x-1, x<02x+1, x0 at x=0

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Solution

fx=2x-1, x<02x+1, x0LHL at x=0=limx0-fx=20-1=-1 RHL at x=0=limx0+fx=20+1=1limx0-fxlimx0+fx
Hence, f(x) is discontinuous at x = 0.

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