Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory:
$[F e F_{6}]^{3 -}$

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Solution

$[F e F_{6}]^{3 -}$
Oxidation state of $F e$ is $+ 3 .$
Orbitals of $F e^{3 +}$ ion.

There are $6 F^{-}$ ions. Thus, it will undergo $d^{2} s p^{3}$ or $s p^{3} d^{2}$ hybridization. As $F^{-}$ is a weak ligand, it does not cause pairing of electrons in the $3 d$ orbitals. Hence the most feasible hybridization is $s p^{3} d^{2}$ .

Hence the geometry of the complex is found to be octahedral.

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