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Question

Discuss the nature of the roots of the equation:
(b+c)x2(a+b+c)x+a=0

A
Real and equal
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B
Real and unequal
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C
Imaginary
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D
None of these
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Solution

The correct option is B Real and unequal
(b+c)x2(a+b+c)x+a=0D=B24AC=(a+b+c)24(a(b+c))=a2+b2+c2+2ab+2bc+2ca4(ab+ac)=a2+b2+c22ab2ac+2bc=(abc)2>0
Hence, the roots are real and unequal

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