Question

Disintegration of $3.7\times {10}^{10}$ atoms per second $(3.7\times {10}^{10}dps)$ is called One _______.

• A. Curie
• B. Bequerel
• C. Geiger
• D. None of these

Answer 1

The correct option is A Curie

`The unit of radioactivity of a substance is measured as the rate at which it changes into daughter nucleus. It has been derived on the scale of disintegration of radium.

The SI unit of activity is dps or Becquerel.

$1$ Curie ($\because 3.7\times {10}^{10}$ dps) $=3.7\times {10}^{10}$ dps $=3.7\times {10}^{10}$ Becquerel $=3.7\times {10}^4$ Rutherford $(\because$ Rd $={10}^6$ dps)