Displacement of a particle is given by the expression $x = 3 t^{2} + 7 t - 9$ , where x is in meter and t is in second. What is acceleration?

1 m / s^{2}

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3 m / s^{2}

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6 m / s^{2}

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9 m / s^{2}

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Solution

The correct option is C $6 m / s^{2}$
Displacement is given as $x = 3 t^{2} + 7 t - 9$
Velocity $v = \frac{d x}{d t} = \frac{d}{d t} (3 t^{2} + 7 t - 9) = 6 t + 7$
Acceleration $a = \frac{d v}{d t} = \frac{d}{d t} (6 t + 7) = 6 m / s^{2}$

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