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Displacement-...

Question

Displacement-time equation of a particle moving along x-axis is
$x = 20 + t^{3} - 12 t$ (SI Units). Find, position and velocity of particle at time $t = 0$ .

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Solution

Displacement of particle $x = 20 + t^{3} - 12 t$ SI units
Position of particle at $t = 0$ s, $x {∣ ∣ ∣}_{t = 0 s} = 20 + 0 - 0 = 20$ m

Velocity of the particle $v = \frac{d x}{d t} = 3 t^{2} - 12$ m/s
$∴$ $v {∣ ∣ ∣}_{t = 0} = 0 - 12 = - 12 m / s$

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