Question

Displacement time equation of a particle SHM is $x=10\sin (\frac{\pi }{3}t+\frac{\pi }{6})cm$. The distance covered by particle in $3s$ is

• A. $5cm$
• B. $20cm$
• C. $10cm$
• D. $15cm$

Answer 1

The correct option is B $20cm$

We have $x=10\sin (\frac{\pi }{3}t+\frac{\pi }{6})cm$

Angular frequency$\omega =\frac{\pi }{3}$

Time period:$T=\frac{2\pi }{3}=6sec$

Amplitude of motion$=10cm$

Particle cover $10cm$ distance in $=\frac{T}{2}=\frac{3}{2}sec$.

So, it will cover $\frac{T}{2}=3sec$ as a distance by $10\times 2=20cm$