0-04- 0-08- 4 is equal to

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Multiplication of Decimals

0.04× 0.08× 4...

Question

$0.04 \times 0.08 \times 4$ is equal to

0.012

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.128

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.00128

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0128

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $0.0128$
Here, $0.04$ has $2$ places decimal and $0.08$ also has $2$ places. So the total decimal places are $4$ .

So, the product will also have $4$ decimalplaces from the right.

$0.04 \times 0.08 \times 4 = 0.0128$

So option D is the correct answer.

Suggest Corrections

Similar questions

Q. Solve :

\frac{0.27 + 0.08}{0.09 + 0.66 + 0.04}

Question 5 (i)
A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days isas follows:
$\begin{matrix} 0.03 & 0.08 & 0.08 & 0.09 & 0.04 & 0.17 0.16 & 0.05 & 0.02 & 0.06 & 0.18 & 0.20 0.11 & 0.08 & 0.12 & 0.13 & 0.22 & 0.07 0.08 & 0.01 & 0.10 & 0.06 & 0.09 & 0.18 0.11 & 0.07 & 0.05 & 0.07 & 0.01 & 0.04 \end{matrix}$
(i) Make a grouped frequency distribution table for this data with class intervals as 0.00 - 0.04, 0.04 - 0.08, and so on.

Q. To find out the concentration of

{S O}_{2}

in the air (in parts per million, i.e.,

p p m

), the data was collected for

30

localities in certain city and is presented below:

Concentration of ${S O}_{2}$ (in ppm)	Frequency
$0.00 - 0.04$	$4$
$0.04 - 0.08$	$9$
$0.08 - 0.12$	$9$
$0.12 - 0.16$	$2$
$0.16 - 0.20$	$4$
$0.20 - 0.24$	$2$

Find the mean concentration of

{S O}_{2}

in the air.

Q. To find out the concentration of

S O_{2}

in the air (in parts per million, i.e., ppm), the data was collected for

30

localities in a certain city and is presented below:

Concentration of $S O_{2}$ (in ppm)	Frequency
$0.00 - 0.04$	$4$
$0.04 - 0.08$	$9$
$0.08 - 0.12$	$9$
$0.12 - 0.16$	$2$
$0.16 - 0.20$	$4$
$0.20 - 0.24$	$2$

Find the mean concentration of

S O_{2}

in the air.

The length and breadth of a field are measured $l = (120 \pm 2) m$ and $b = (100 \pm 5) m$ respectively. What is the area of the field?

Join BYJU'S Learning Program

0.04×0.08×4 is equal to

The correct option is C 0.0128Here, 0.04 has 2 places decimal and 0.08 also has 2 places. So the total decimal places are 4. So, the product will also have 4 decimalplaces from the right.0.04×0.08×4=0.0128So option D is the correct answer.

$0.04 \times 0.08 \times 4$ is equal to

The correct option is C $0.0128$
Here, $0.04$ has $2$ places decimal and $0.08$ also has $2$ places. So the total decimal places are $4$ .

So, the product will also have $4$ decimalplaces from the right.

$0.04 \times 0.08 \times 4 = 0.0128$

So option D is the correct answer.