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Question

504x+44x+4+49x

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Solution

Consider the given integral.

I=504x+44x+4+49xdx ……. (1)

We know that

baf(x)dx=baf(a+bx)dx

Therefore,

I=5045x+445x+4+49(5x)dx

I=5049x49x+44+xdx

I=5049x49x+4x+4dx …… (2)

On adding equation (1) and (2), we get

I=5049x+4x+449x+4x+4dx

I=501dx

I=[x]50

I=50

I=5

Hence, this is the answer.


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