$1^{13} + 2^{13} + 3^{13} + . . . . + 60^{13}$ is divisible by

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Solution

The correct option is A 61
When n is an odd number $(x^{n} + a^{n})$ is always divisible by $(x + a)$
In expression $1^{13} + 2^{13} + 3^{13} + . . . . . . + 60^{13}$ is divisible by $(60 + 1) = 61$

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