1-1-4- 3-1-4- 32-1-4- 33 is equal to

The correct option is A 1.120 Given expression = #160; 1+1/12+1/36+1/108=108+9+3+1/108=121/108=1.120 ( approx ) ...

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Derivative from First Principle

1+1/4× 3+1/4×...

Question

$1 + \frac{1}{4 \times 3} + \frac{1}{4 \times 3^{2}} + \frac{1}{4 \times 3^{3}}$ is equal to

1.120

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1.250

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1.140

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1.160

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Solution

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Similar questions

1 + \frac{1}{4 \times 3} + \frac{1}{4 \times 3^{2}} + \frac{1}{4 \times 3^{3}} + \frac{1}{4 \times 3^{4}}

\frac{1}{3} + \frac{2}{3^{2}} + \frac{3}{3^{3}} + \frac{4}{3^{4}} + \dots \infty

\frac{1}{3} + \frac{2}{3^{2}} + \frac{3}{3^{3}} + \frac{4}{3^{4}} + \dots \infty

S_{\infty} = 1 + \frac{4}{3} + \frac{9}{3^{2}} + \frac{16}{3^{3}} + \dots \dots

2 S_{\infty}

\sqrt{2 \frac{1}{4}} \times {(1 \frac{1}{3})}^{2} + 1 \div 3 \sqrt{3 \frac{3}{8}} =

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