Question

$2{SO}_2+O_2\to 2{SO}_3$
With the help of the above reaction equation, determine the maximum number of moles of $S{O}_3$ can be produced, if $0.25$ moles of sulfur dioxide is mixed with $0.25$ moles of oxygen?

• A. $0.0625$ mole
• B. $0.125$ mole
• C. $0.25$ mole
• D. $0.5$ mole
• E. $1.0$ mole

Answer 1

The correct option is C $0.25$ mole

$2{SO}_2+O_2\to 2{SO}_3$
As per the balanced chemical equation, 2 moles of $S{O}_2$ will react with 1 mole of $O_2$ to form 2 moles of $S{O}_3$.
Hence, 0.25 moles of $S{O}_2$ will react with $0.25\times \frac{1}{2}=0.125$ mole of $O_2$ to form $0.25\times \frac{2}{2}=0.25$ moles of $S{O}_3$.
Hence, the maximum number of moles of $S{O}_3$ that can be produced is 0.25 moles.