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Question

2×3+612÷4=17

A
×and+
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B
+and
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C
+and÷
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D
and÷
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Solution

The correct option is A ×and+
On interchanging ×and+, we get :
Given expression : =2+3×612÷4
=2+3×612÷4
=2+3×63
=2+183=17

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