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Byju's Answer
Standard VII
Mathematics
Dividing a Monomial by a Monomial
27a2x2-48b2=
Question
27
a
2
x
2
ā
48
b
2
=_____
A
(
9
a
x
−
16
b
)
(
3
a
x
−
3
b
)
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B
(
3
a
x
−
16
b
)
(
9
a
x
−
3
b
)
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C
3
(
3
a
x
+
4
b
)
(
3
a
x
−
4
b
)
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D
3
(
3
a
x
+
6
b
)
(
3
a
x
−
4
b
)
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Solution
The correct option is
C
3
(
3
a
x
+
4
b
)
(
3
a
x
−
4
b
)
27
a
2
x
2
−
48
b
2
=
3
(
9
a
2
x
2
−
16
b
2
)
=
3
{
(
3
a
x
)
2
−
(
4
b
)
2
}
=
3
(
3
a
x
+
4
b
)
(
3
a
x
−
4
b
)
Suggest Corrections
0
Similar questions
Q.
Solve
(
3
a
+
4
b
)
×
(
4
a
+
3
b
)
Q.
Simplify:
(
2
a
+
3
b
)
(
5
a
+
4
b
)
Q.
∣
∣ ∣
∣
a
+
b
a
+
2
b
a
+
3
b
a
+
2
b
a
+
3
b
a
+
4
b
a
+
4
b
a
+
5
b
a
+
6
b
∣
∣ ∣
∣
=
Q.
Solve :
2
a
−
[
4
b
−
{
4
a
−
(
3
b
−
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
2
a
+
2
b
)
}
]
Q.
Simplify:
2
a
-
[
4
b
-
{
4
a
-
(
3
b
-
2
a
+
2
b
)
}
]
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