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Question

27a2x2āˆ’48b2=_____

A
(9ax16b)(3ax3b)
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B
(3ax16b)(9ax3b)
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C
3(3ax+4b)(3ax4b)
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D
3(3ax+6b)(3ax4b)
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Solution

The correct option is C 3(3ax+4b)(3ax4b)
27a2x248b2
= 3(9a2x216b2)=3{(3ax)2(4b)2}
= 3(3ax+4b)(3ax4b)

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