$2 A l (s) + 6 H C l (a q) \to 2 {A l}^{3 +} (a q) + 6 {C l}^{-} (a q) + 3 H_{2} (g)$
The reaction above is best described as a(an):

precipitation reaction

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acid/base reaction

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redox reaction

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combustion reaction

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decomposition reaction

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Solution

The correct option is D redox reaction
Option $C$ is the correct answer.
In the given equation, $A l$ has $0$ oxidation state in the left hand side. Whereas, in the right hand side, its oxidation number has become $+ 3$ . Which means, $A l$ got oxidized.
$H$ has $+ 1$ oxidation state in the left hand side. Whereas, in the right hand side, its oxidation number has become $0$ (molecular state). Which means, $H$ got reduced.
Thus it is a redox reaction.

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