Given (2√( 3 ) +3√( 2 ) ) (3√( 2 ) 2√( 3 ) ) This is of the form : (a+b) × (a b) = a^2 b^2 Here a=3√(2) and b = 2√(3) On multiplying the ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Special Products

3√2-2√32√3+3√...

Question

$(3 \sqrt{2} - 2 \sqrt{3}) (2 \sqrt{3} + 3 \sqrt{2}) =$

Open in App

Solution

Given $(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{2} - 2 \sqrt{3})$
This is of the form : $(a + b) \times (a - b) = a^{2} - b^{2}$
Here $a = 3 \sqrt{2}$ and $b = 2 \sqrt{3}$
On multiplying the $2$ brackets we get, $9 \times 2 - 4 \times 3$
$= 6$

Suggest Corrections

Similar questions

\frac{4 + \sqrt{5}}{4 - \sqrt{5}} + \frac{4 - \sqrt{5}}{4 + \sqrt{5}}

\frac{1}{\sqrt{3} + \sqrt{2}} - \frac{2}{\sqrt{5} - \sqrt{3}} - \frac{3}{\sqrt{2} - \sqrt{5}}

\frac{2 + \sqrt{3}}{2 - \sqrt{3}} + \frac{2 - \sqrt{3}}{2 + \sqrt{3}} + \frac{\sqrt{3} - 1}{\sqrt{3} + 1}

\frac{2 \sqrt{6}}{\sqrt{2} + \sqrt{3}} + \frac{6 \sqrt{2}}{\sqrt{6} + \sqrt{3}} - \frac{8 \sqrt{3}}{\sqrt{6} + \sqrt{2}}

(3 \sqrt{2} + 2 \sqrt{3}) (2 \sqrt{3} - 4 \sqrt{2})

If \int \frac{d x}{\sqrt{x^{2} - 3 x + 2}} = log (A | + C, then A =

\frac{(3 \frac{2}{3})^{2} - (2 \frac{1}{2})^{2}}{(4 \frac{3}{2})^{2} - (3 \frac{1}{3})^{2}}

\div

\frac{3 \frac{2}{3} - 2 \frac{1}{2}}{4 \frac{3}{2} - 3 \frac{1}{3}}

Evaluate:

$(i) (\frac{5}{3})^{2} \times (\frac{5}{3})^{2}$

$(i i) (\frac{5}{6})^{6} \times (\frac{5}{6})^{- 4}$

$(i i i) (\frac{2}{3})^{- 3} \times (\frac{2}{3})^{- 2}$

$(i v) (\frac{9}{8})^{- 3} \times (\frac{9}{8})^{2}$

Join BYJU'S Learning Program