Question

$3\sqrt[4]{42}>2\sqrt[4]{46}$
If true then enter $1$ and if false then enter $0$

Answer 1

$3\sqrt[4]{42}=\sqrt[4]{481\times 2}=\sqrt{162}$
$2\sqrt[4]{46}=\sqrt[4]{416\times 6}=\sqrt{96}$
Since $162>96;3\sqrt[4]{42}>2\sqrt[4]{46}$