Question

$4s^2$ is the configuration of the outermost orbit of an element. Its atomic number would be:

• A. 29
• B. 24
• C. 30
• D. 19

Answer 1

The correct option is C 30

$4s^2$ is the configuration of the outermost orbit of an element Its atomic number would be 30. The element is zinc. Its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^2$.