The correct option is B 120 n _ P _ r = n! / (n r)! So, 5 _ P _ 4 = 5! / (5 4)! = 5! / 1! #160; = 5 ! = 5 × 4 × 3 × 2 × 1 = 120 (Since ...

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5P4=.

Question

$^{5} P_{4} =$ ____.

720

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120

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60

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360

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Solution

The correct option is B $120$
${n_{P}}_{r} = \frac{n!}{(n - r)!}$
So, ${5_{P}}_{4} = \frac{5!}{(5 - 4)!} = \frac{5!}{1!} = 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$ (Since $1! = 1)$

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