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Byju's Answer

Standard XII

Chemistry

Difference between Internal Energy and Enthalpy

611C on decay...

Question

$_{6}^{11} C$ on decay produces:

positron

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β

particle

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α

particle

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None of these

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Solution

The correct option is B positron
$C_{6}^{11} \to B_{5}^{11} + e^{+} + v_{e} + 0.96 M e V$

There is a positron emission in the $C_{6}^{11}$ decay.
So Option A is correct

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Similar questions

_{6}^{11} C

on decay produces

Write symbolically the nuclear $β^{+}$ decay process of $6^{11} C$ . Is the decayed product X an isotope or isobar of $(6^{11} C)$ ? Given the mass values m $(6^{11} C)$ = 11.011434 u and m (X) = 11.009305 u. Estimate the Q-value in this process.

Q. Write nuclear reaction equations for :
(i)

α

- decay of

_{88}^{226} R a

(ii)

α

- decay of

_{94}^{242} P u

(iii)

β^{-}

- decay of

_{15}^{32} P

(iv)

β^{-}

- decay of

_{83}^{210} B i

(v)

β^{+}

- decay of

_{6}^{11} C

(vi)

β^{+}

- decay of

_{43}^{97} T c

(vii) Electron capture of

_{54}^{120} X e

_{83} {B i}^{212}

decays with parallel radioactive reactions resulting in

_{81} {Ti}^{208}

and

_{84} {Po}^{212}

by emitting

α and β

particles respectively. The

α and β

decay processes have decay constants

λ_{1} and λ_{2}

. Mean lifetime of

_{83} {Bi}^{212}

500

seconds. If

_{81} {Ti}^{208}

and

_{84} {Po}^{212}

are produced in ratio of

9 : 16

then

_{92}^{235} U

decays with emission of

α

and

β -

particles to form ultimately

_{82}^{207} P b

. How many

α -

and

β -

particles are emitted per atom of

P b

produced?

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116C on decay produces:

The correct option is B positronC116→B115+e++ve+0.96MeVThere is a positron emission in the C116 decay.So Option A is correct

$_{6}^{11} C$ on decay produces:

The correct option is B positron
$C_{6}^{11} \to B_{5}^{11} + e^{+} + v_{e} + 0.96 M e V$

There is a positron emission in the $C_{6}^{11}$ decay.
So Option A is correct