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Question

6y27y5=_____

A
(3y+5)(2y1)
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B
(3y5)(2y+1)
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C
(3y5)(2y1)
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D
(3y+5)(2y+1)
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Solution

The correct option is A (3y5)(2y+1)
6y27y5
=6y2+3y10y5
=3y(2y+1)5(2y+1)
=(3y5)(2y+1)

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