Given (7 √( 7 ) )× (7+√( 7 ) ) This is of the form : (a+b) × (a b) = a^2 b^2 Here a=7 and b = √(7) Multiplying the 2 brackets, we get ...

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Byju's Answer

Standard XII

Mathematics

Definition of Functions

7-√77+√7 =

Question

$(7 - \sqrt{7}) (7 + \sqrt{7}) =$

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Solution

Given $(7 - \sqrt{7}) \times (7 + \sqrt{7})$
This is of the form : $(a + b) \times (a - b) = a^{2} - b^{2}$
Here $a = 7$ and $b = \sqrt{7}$
Multiplying the 2 brackets, we get
$49 - 7 = 42$

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Similar questions

Question 109 (ii)

Observe the following patterns and fill in the blanks to make the statements true:
$7 \times 4 = 28$
$7 \times 3 =$ ___ $= 28 - 7$
$7 \times 2 =$ ___=___ $= - 7$
$7 \times 1 = 7 =$ ___ $- 7$
$7 \times 0 =$ ___ =___-___
$7 \times (- 1) = - 7 =$ ___-___
$7 \times (- 2) =$ ___=___-___
$7 \times (- 3)$ ___=___-___

77 + 7 \times 2 \div 4 - 7 = 19

Q. 77 + 7

\times

\div

4 - 7 = 19

Q. Simplify the following using distributive property

7 + 77 + 777 + 7 \times 9 + 77 \times 99 + 777 \times 999

Express as rupees using decimals:

(i) 7 paise (ii) 7 rupees 7 paise (iii) 77 rupees 77 paise

(iv) 50 paise (v) 235 paise

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(7−√7)(7+√7)=

Given (7−√7)×(7+√7)This is of the form : (a+b)×(a−b)=a2−b2Here a=7 and b=√7Multiplying the 2 brackets, we get49−7=42

$(7 - \sqrt{7}) (7 + \sqrt{7}) =$

Given $(7 - \sqrt{7}) \times (7 + \sqrt{7})$
This is of the form : $(a + b) \times (a - b) = a^{2} - b^{2}$
Here $a = 7$ and $b = \sqrt{7}$
Multiplying the 2 brackets, we get
$49 - 7 = 42$