a1i+a2j is a unit vector perpendicular to 4i-3j if
A
at=.6,a2=.8
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B
a1=3,a2=4
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C
a1=.8,a2=.6
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D
a1=4,a2=3
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Solution
The correct option is Aat=.6,a2=.8 a1i+a2j is a unit vector perpendicular to 4i−3j Therefore, 4a1−3a2=0 ....(1) Given that √a12+a22=1 ....(2) Solving (1) and (2): a1=0.6 and a2=0.8