$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$ divided by $a^{2} + 2 a b + b^{2}$ is

a^{2} + b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a + 2 b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 a^{2} + b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a + b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $a + b$
$a^{2} + 2 a b + b^{2}$ $a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$
$a^{3} + 2 a^{2} b + a b^{2}$
$a + b$
$a^{2} b + 2 a b^{2} + b^{3}$
$a^{2} b + 2 a b^{2} + b^{3}$
$0$

Suggest Corrections

Similar questions

Q. What should be subtracted from

2 a^{2} - b^{2} + 3 a^{2} b

to get

a^{2} + b^{2} + 3 a b^{2} - 6 ?

Q. Which of the following equations are correct?

(i) (a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2 (a b + b c + c a)

(i i) (a + b)^{3} = a^{3} + b^{3} + 3 a b (a - b)

(i i i) (a - b)^{3} = a^{3} - b^{3} - 3 a b (a + b)

(i v) a^{2} - b^{2} = (a + b) (a - b)

Which of the following equation/s is/are correct?

$i) (a + b + c)^{2} = a^{2} + b^{2} + c^{2} - 2 (a b + b c + c a)$
$i i) (a + b)^{3} = a^{3} + b^{3} + 3 a b (a - b)$
$i i i) (a - b)^{3} = a^{3} - b^{3} - 3 a b (a + b)$
$i v) a^{2} - b^{2} = (a + b) (a - b)$

If a, b, c are in G.P., prove that:

(i) $a (b^{2} + c^{2}) = c (a^{2} + b^{2})$

(ii) $a^{2} b^{2} c^{2} (\frac{1}{a^{3}} + \frac{1}{b^{3}} + \frac{1}{c^{3}}) = a^{3} + b^{3} + c^{3}$

(iii) $\frac{(a + b + c)^{2}}{a^{2} + b^{2} + c^{2}} = \frac{a + b + c}{a - b + c}$

(iv) $\frac{1}{a^{2} - b^{2}} + \frac{1}{b^{2}} = \frac{1}{b^{2} - c^{2}}$

(v) $(a + 2 b + 2 c) (a - 2 b + 2 c) = a^{2} + 4 c^{2}$ .

Q. Simplify the following expressions.

\frac{a^{2} - b^{2}}{a - b} - \frac{a^{3} - b^{3}}{a^{2} - b^{2}}

Join BYJU'S Learning Program

$a^{2} + 2 a b + b^{2}$	$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$ $a^{3} + 2 a^{2} b + a b^{2}$	$a + b$
	$a^{2} b + 2 a b^{2} + b^{3}$ $a^{2} b + 2 a b^{2} + b^{3}$
	$0$

a3+3a2b+3ab2+b3 divided by a2+2ab+b2 is

The correct option is D a+b a2+2ab+b2 a3+3a2b+3ab2+b3 a3+2a2b+ab2 a+b a2b+2ab2+b3 a2b+2ab2+b3 0

$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$ divided by $a^{2} + 2 a b + b^{2}$ is

The correct option is D $a + b$
$a^{2} + 2 a b + b^{2}$ $a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$
$a^{3} + 2 a^{2} b + a b^{2}$
$a + b$
$a^{2} b + 2 a b^{2} + b^{3}$
$a^{2} b + 2 a b^{2} + b^{3}$
$0$