The correct option is A 0 a.b=( i + j + k #160;) .( i j + k #160;) =1 1+1=1 b.c=( i j + k #160;) .( i + j k #160;) ...

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Applications of Dot Product

a.b+b.c÷ c.a

Question

$(a . b) + (b . c) \div (c . a)$

0

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\frac{1}{2}

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\frac{1}{3}

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2

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Solution

The correct option is A $0$
$a . b = (ˆ i + ˆ j + ˆ k) . (ˆ i - ˆ j + ˆ k) = 1 - 1 + 1 = 1 b . c = (ˆ i - ˆ j + ˆ k) . (ˆ i + ˆ j - ˆ k) = 1 - 1 - 1 = - 1 c . a = (ˆ i + ˆ j - ˆ k) . (ˆ i + ˆ j + ˆ k) = 1 + 1 - 1 = 1$
Now $(a . b) + (b . c) \div (c . a) = 1 + \frac{(- 1)}{(1)} = 0$

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