A- a b- b a - and A2 - - - - - - then

The correct option is A α=a^2+b^2,β =2ab A^2=AA=[ a amp;b; b nbsp; amp;a ][ a amp;b; b nbsp; amp;a ] =[ a^2+b^2 amp;2ab ...

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Multiplication of Matrices

A=[ a b; b a ...

Question

$A = [\begin{matrix} a & b b & a \end{matrix}]$ and $A^{2} = [\begin{matrix} α & β β & α \end{matrix}]$ then

α = a^{2} + b^{2}, β = 2 a b

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α = a^{2} + b^{2}, β = a^{2} - b^{2}

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α = 2 a b, β = a^{2} + b^{2}

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α = a^{2} + b^{2}, β = a b

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Similar questions

If A = [\begin{matrix} a & b b & a \end{matrix}] and A^{2} = [\begin{matrix} α & β β & α \end{matrix}], then

A = [\begin{matrix} a & b b & a \end{matrix}]

A^{2} = [\begin{matrix} α & β β & α \end{matrix}]

A = [\begin{matrix} a & b b & a \end{matrix}]

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cos θ + b sin θ = c

cos (α - β) = \frac{2 c^{2} - (a^{2} + b^{2})}{a^{2} + b^{2}}

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